5-2[x-1+2(x-1)]=1

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Solution for 5-2[x-1+2(x-1)]=1 equation: 


Simplifying
5 + -2[x + -1 + 2(x + -1)] = 1

Reorder the terms:
5 + -2[x + -1 + 2(-1 + x)] = 1
5 + -2[x + -1 + (-1 * 2 + x * 2)] = 1
5 + -2[x + -1 + (-2 + 2x)] = 1

Reorder the terms:
5 + -2[-1 + -2 + x + 2x] = 1

Combine like terms: -1 + -2 = -3
5 + -2[-3 + x + 2x] = 1

Combine like terms: x + 2x = 3x
5 + -2[-3 + 3x] = 1
5 + [-3 * -2 + 3x * -2] = 1
5 + [6 + -6x] = 1

Combine like terms: 5 + 6 = 11
11 + -6x = 1

Solving
11 + -6x = 1

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.
11 + -11 + -6x = 1 + -11

Combine like terms: 11 + -11 = 0
0 + -6x = 1 + -11
-6x = 1 + -11

Combine like terms: 1 + -11 = -10
-6x = -10

Divide each side by '-6'.
x = 1.666666667

Simplifying
x = 1.666666667

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